JEE Main 2014 – Normalization method for XII board marks

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JEE Main 2014, normalization method for XII board marks

According to sources this year again CBSE will give 40% weight-age to XII board marks after normalization of board marks for preparation of final JEE Main 2014 all india rank. The normalization method that was adopted in 2013 is explained below. CBSE might implement some changes in Normalization process of board marks in 2014.

Reportedly this year Odisha and Maharashtra state will also join JEE Main. Gujarat has already joined JEE Main in 2013. So all candidates who wants to take admission in engineering colleges that comes under Maharashtra, Odisha and Gujarat are requested to apply for JEE Main 2014

Normalization method used in 2013

In view of large scale variations in the examination system in country, the JEE Interface
Group (JIG) decidedin 2013 that 50% of Boards marks be normalized by
equating percentile amongst different boards/examining bodies and anchoring them to
All India JEE-Main percentiles, and 50% be normalized by equating each
Board’s/examining Body’s percentile with JEE(Main) percentile marks of respective
Boards /examining bodies.

Accordingly, the detailed procedure for normalization of Board marks was as follows:-

  • Note down the aggregate marks (A0) obtained by each student in JEE- Main.
  • Compute the percentile (P) of each student on the basis of aggregate marks in his/her own board (B0) computed from the list of five subjects specified (each marked out of 100). The percentile is to be computed among all students of the board whose subject combinations meet the eligibility criteria of JEE-Main.
  • Determine the JEE- Main aggregate marks corresponding to percentile (P) at the All- India level. Regard this as B1.
  • Also, determine the JEE- Main aggregate marks corresponding to percentile (P) among the set of aggregate scores obtained in the JEE- Main by the students of that board. Regard this as B2.

The normalized board score of the candidate was computed as:

Bfinal = 0.5 * (B1 + B2)

For the purpose of admission to NITs/CFTIs/SFTIs it was decided to use the JEE Mains performance and the Normalized Board performance in the 60:40 ratio, the composite score for drawing the merit list was computed as:

C = 0.6 * AO + 0.4 * Bfinal,

Five subjects to be used for normalization:-

1. Physics
2. Mathematics
3. Any one of the subjects Chemistry, Biology, Biotechnology and Computer Science
4. One language
5. Any subject other than the above four subjects.

In respect of 3, 4 and 5, the best mark in a given category was chosen.

Many students filed petition in courts against this JEE Main normalization process, court is still pending in Supreme Court.

Latest update on JEE Main Normalization process of XII Marks

Update on 11th July 2013 – CBSE accepted formula was wrong but they continued with this normalization method for 2013, read complete news here.

Case was still pending in AP high court and final hearing was scheduled on 17th July.

Update on 17th July 2013 – CBSE requested AP high court to transfer this case to Supreme court so AP high court transferred this case to SC.

CBSE ignore ISI inputs – According to sources CBSE ignore ISI inputs before finalizing Normalization method of class XII marks – Read complete news here

Case is still pending and next hearing is scheduled in month of November.- Read here

A short example to show major flaw in JEE Main 2013 normalization method of XII Marks

A student scoring 92% in CBSE Boards (getting 96.5%ile will get 0.4*80 = 32 marks out of 144)

A student scoring 96% in CBSE Boards (getting 99.6%ile will get around 0.4*300 = 120 marks out of 144)

A mere difference of 20 marks in boards (which should have ideally contributed 0.4*20 = 8 marks difference in final ranking) gets amplified by a factor of 1100% (120-32 = 88), and thousands of students will lose out in the new system.

Best wishes for JEE 2014 Aspirants

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